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8t^2+66t+16=0
a = 8; b = 66; c = +16;
Δ = b2-4ac
Δ = 662-4·8·16
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-62}{2*8}=\frac{-128}{16} =-8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+62}{2*8}=\frac{-4}{16} =-1/4 $
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